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f(x)= (lnx)/(1+(lnx)^2) for x in (0, ∞). find lim(x-->0+) and lim(x-->∞)
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both limits go to 0
to show it algebraically , use L'Hopitals rule differentiate top and bottom separately \[\rightarrow \frac{\frac{1}{x}}{\frac{2\ln(x)}{x}} = \frac{1}{2 \ln(x)}\] then evaluating this as x->0+ and x->inf
thanks so much for your help :) I had been working on this problem for a while now.
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