Question

(x^-2*z^5/3)^1/3

simplify

Answer 1

(x^(-2)*(z^(5))/(3))/(3)

Remove the negative exponent in the numerator by rewriting x^(-2) as (1)/(x^(2)). A negative exponent follows the rule: a^(-n)=(1)/(a^(n)).
((1)/(x^(2))*(z^(5))/(3))/(3)

Multiply 1 by z^(5) to get z^(5).
((z^(5))/(3*x^(2)))/(3)

Multiply x^(2) by 3 to get 3x^(2).
((z^(5))/(3x^(2)))/(3)

Multiply the factor by the rest of the expression to remove the fraction from the denominator. To multiply by a factor in the denominator, multiply by 1 over the factor.
(1)/(3)*(z^(5))/(3x^(2))

Multiply 1 by z^(5) to get z^(5).
(z^(5))/(3x^(2)*3)

Multiply 3 by 3x^(2) to get 9x^(2).
(z^(5))/(9x^(2))