Question

derivatives of trigonometric function!

Answer 1

\[y=(2x+3)^{2}\sin(x-6)\]

Answer 2

if u want to take the derivative of the equation u should use the product rule. try that

Answer 3

im a little bit confused

Answer 4

so for the product rule use uv = u'v + uv', where u = (2x + 3)^2: v = sin(x-6)

Answer 5

and u' and v' are the deritives of u and v

Answer 6

still confused?

Answer 7

yah

Answer 8

the solving part im confused

Answer 9

ok so take the deritive of u = (2x + 3)^2, what is it?

Answer 10

2(2x+3) ??

Answer 11

the answer should be 4(2x+3)

Answer 12

why?

Answer 13

u forgot to take the deritive inside the brackets (chain rule)

Answer 14

ahh like this 2(2x+3)(2) ??

Answer 15

yup

Answer 16

now do it for the v = sin(6x-1)

Answer 17

6cos(6x-1) ????

Answer 18

yup

Answer 19

now put it all together with the equation uv = u'v + uv' and that should be your answer

Answer 20

a good website if u want to see step by step instructions is http://calc101.com/, but don't get addicted lol

Answer 21

ok tnx

Answer 22

the website is not found??

Answer 23

google calc101 should be the first link

Answer 24

this is interesting tnx for the info

Answer 25

np