Help me on this question please... I really dont know where to start thanks!!

Question

kuoministers · Answer

$$\huge3^{x} + 5 \times 3^{x} = 54$$

deadshot · Answer

to start, we need to isolate the variables, we start by dividing both sides by 3^x, then subtract 5 from both sides, and then multiply both sides by 3^x
$$3^x + 5 \times 3^x \div 3^x = 54 \div 3^x$$
$$3^x + 5 - 5 = 54/3^x$$

deadshot · Answer

$$3^x \times 3^x = 54/3^x \times 3^x - 5$$

deadshot · Answer

$$9^x^2 = 54 -5$$

deadshot · Answer

$$9^x^2 = 51$$
so now we find the square root of each side

deadshot · Answer

$$\sqrt{9^x^2} = \sqrt{51}$$

deadshot · Answer

the square and square root cancel each other out, so it would be $$9^x \approx 7 $$

kuoministers · Answer

im not sure but thats not the answer that is in the back of the book :P

deadshot · Answer

divide both sides by 9
$$9^x \div 9 = 7 \div 9$$
$$^x = 7/9$$

kuoministers · Answer

@artix_17

kuoministers · Answer

thats not the answer in the book :P

anonymous · Answer

whats your answer?

kuoministers · Answer

2

kuoministers · Answer

i think the way he started the question was wrong cause i was told to keep the same base

anonymous · Answer

Yea, 3^x X 3^x can be written as 3^2x

kuoministers · Answer

yea i agree on that

kuoministers · Answer

$$\huge3^{2x} + 5 = 3^{3} \times 2$$
this might help?

anonymous · Answer

How did you get that?

anonymous · Answer

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