Mathematics
5 Online
OpenStudy (anonymous):
CAn U find the derivative for this equation PLZ TT^TT
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OpenStudy (anonymous):
\[\sin (xy)+^{2} = x -y\]
OpenStudy (anonymous):
oh no -.-
OpenStudy (anonymous):
\[\sin (xy) + x^{2} = x - y\]
OpenStudy (anonymous):
oh boy..... I'm sorry, but I didnt do very well in Geometry... :-/
OpenStudy (anonymous):
:] weeee xD
everybody is smart except me
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OpenStudy (anonymous):
thats calculas -.-
OpenStudy (anonymous):
O_O
OpenStudy (anonymous):
who can solve this TT___TT
OpenStudy (anonymous):
i tell you what i got
OpenStudy (anonymous):
and i know its wrong
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OpenStudy (anonymous):
\[y \prime(xy+y) = -\cos (xy)y-2x\]
OpenStudy (anonymous):
it wrong i know -..-
OpenStudy (aravindg):
please do not underestimate yourself!! we are all people just like you :)
OpenStudy (anonymous):
please !!!
i thought u were going to type the answer
OpenStudy (anonymous):
=_=
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OpenStudy (aravindg):
i am doing on paper 1 sec :)
OpenStudy (anonymous):
:B
OpenStudy (aravindg):
do you want to solve for y' ?
OpenStudy (anonymous):
yup
OpenStudy (aravindg):
ok lets do it together take first term
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OpenStudy (aravindg):
first you will get \[\cos xy \]
apply chain rule and use product rule for xy
OpenStudy (aravindg):
that will be?
OpenStudy (anonymous):
\[y \prime =\frac{ -\cos (xy)y -2x }{ (xy+y) }\] ?
OpenStudy (aravindg):
there is a mistake ..lets do afresh that will help you more :)
OpenStudy (aravindg):
so answer my qn above did you differentiate first term ?
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OpenStudy (aravindg):
tell me what you get?
OpenStudy (anonymous):
cos (xy) (y+x y prime ) ??
OpenStudy (aravindg):
yep :)
\[\cos (xy)(xy'+y) \]
who told you are dump ?
OpenStudy (aravindg):
now next term :)
OpenStudy (aravindg):
\[\dfrac{dy}{dx} x^2=?\]
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OpenStudy (anonymous):
cos(xy)(xy′+y)+2x = -y′
OpenStudy (aravindg):
good but there is a small mistake :) check again ?
OpenStudy (anonymous):
i see no mistake sir -.-
OpenStudy (anonymous):
oh right ;B
OpenStudy (anonymous):
cos(xy)(xy′+y)+2x = 1 -y′
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OpenStudy (aravindg):
:) now i feel like i am dump :P
OpenStudy (anonymous):
xD ..
its okie i think i got it now
OpenStudy (anonymous):
thanks
OpenStudy (aravindg):
:) good ..a medal for your intelligence XD
OpenStudy (anonymous):
:P
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OpenStudy (anonymous):
thanks and bye ..
;) talk to u later igtg complete studying :B
OpenStudy (aravindg):
ok best of luck :)