HELPPPPP PLEZZZZZZZZZ
i need help
1) Since both the other angles of the triangle are 45° each, its safe to say that it is an isosceles triangle and hence the sides other than the hypotenuse will have the same dimension. Let the length of the side be ' x ' so by Pythagoras theorem we have x^2 + x^2 = 12 so we have 2 x^2 = 12 -> x^2 = 6 -> x = square root of 6 = 2.449 = 2.45 units 2) referring to a figure that you may draw with ease, in the given question the shorter side is opposite to 30° and the longer side is adjacent to 30°. Let the shorter side be ' x ' and the longer side be ' y '. so we have sin 30 = x / 18 -> x = 18 sin 30 = 18 / 2 = 9cm thats for question 2 idk number 1 and we have cos 30 = y / 18 so y = 18 cos 30 = 15.588 = 15.59cm 3) for a right triangle we know that the sum of the squares of the 2 sides must be equal to the square of the hypotenuse (Pythagoras Theorem) since 5^2 + 5 ^2 = 50 and 8^2 = 64, we can see that they are not equal and hence these values cannot be the sides of a right triangle. So Andrew is wrong. a
so confusing but good
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1) We have 3 angles in d qstion..30,60 and 90 leg facing 30 is shorter leg ie. perpendicular leg facing 60 is longer leg i.e base leg facing 90 is longest leg i.e hypotenuse now, we have to find d relation btw shorter n longer leg. using d formula tan x = perpendicular / base = shorter leg/longer leg we get...tan 30 = shorter leg / longer leg 1/sq.rt 3 = shorter leg/longer leg longer leg = sq .rt 3 times the shorte leg
omg its not letting me in
what bb collobrate
yes
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