Determine where each of function is continuous.

k(x)=√(4-2x)
(Use interval notation)
I believe it's x=2.

I did 4-2x=0
got -2x=-4
then divided by -2 on both sides.
got x=2.

So I figured it would be discontinuous at x=2 but on either side its infinity.

So I was thinking it would be (-infinity, 2]U[2, infinity) but not sure if that is how I would put it in too interval notation.

Question

Determine where each of function is continuous.

k(x)=√(4-2x)
(Use interval notation)
I believe it's x=2.

I did 4-2x=0
got -2x=-4
then divided by -2 on both sides.
got x=2.  

So I figured it would be discontinuous at x=2 but on either side its infinity. 

So I was thinking it would be (-infinity, 2]U[2, infinity) but not sure if that is how I would put it in too interval notation.

anonymous · Answer

here the case is different
you have to choose such value of x such that 4-2x is always poisitive

anonymous · Answer

So -infinity to 2 would be the interval.

anonymous · Answer

exactly

anonymous · Answer

(-infi, 2]

anonymous · Answer

that is in interval notation correct?

anonymous · Answer

yees