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OpenStudy (anonymous):
A 0.0182g sample of an unknown substance was dissolved in 2.135g of benzene. Molality of solution is 0.0698m. What is the molecular mass of unknown?
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OpenStudy (chmvijay):
122.75 is molecular weight
OpenStudy (anonymous):
How did you get that?
OpenStudy (chmvijay):
is it right
OpenStudy (anonymous):
Can you show your work? I need to understand how you got the answer.
OpenStudy (chmvijay):
Molality = moles of solute(n)/ gram of solvent(GS) but moles of solute = gram of solute(G) /molecular weight of solvent(M) molality =(G/M) /GS except M you know all the things
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OpenStudy (chmvijay):
final answer you have to multiply by 1000 bcoz you are doing it molality thats why
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