Question

Solve the following radical equation (sqrt of 4z+41) +3 = z+2

Answer 1

\[\sqrt{4z+41}+3=z+2\]

Subtracting 3 from both sides gives:
\[\sqrt{4z+41}=z-1\]
The next step is to square both sides. Can you do that?

Answer 2

okay i got 4z+41=z^2-2z+1

Answer 3

Good!. Now subtract 4z and 41 from both sides to get a quadratic of the form
\[az ^{2}+bz+c=0\]