Question

Given that AE is a tangent of the circle with the center at B, BC = 3.5, and AE = 24, which is the length of EC?

Answer 1

drawwwwwwwwwwwwwww it :)

Answer 2

there you go

Answer 3

pythagorean theorem ;)

Answer 4

A. 7 B. 13 C. 25 D. 49

Answer 5

you have a right triangle.... the chord AC is a diameter

tangents and a radius intersect at right angles so angle EAB = 90

BC = 3.5 so AC = 7 (2 radii in a diameter)


EC is found by Pythagoras' theorem

EC^2=AE^2+AC^2


EC^2=24^2+7^2

Answer 6

You can solve for the rest

Answer 7

@qudder17
Look at the attached diagram. If you know your Pythagorean triples, you can answer the question without any calculation.
Otherwise, use the Pythagorean Theorem as instructed above.