need help here
which one can you do in 17
nothing ;(
my prof didnt explain that. ;/
\[\lim_{x \rightarrow a^{+}}f(x)\] means the limit of f when we come towards a from the right so you will move your hand from the far right towards that a ,for \[a^{-}\] you do the same from the left
-->
for \[\lim_{x \rightarrow 3^{+}}\] look at the y value at -3
when x=-3 , y=?
hello
-2
yes notice that it is not shaded so y=1 where it is shaded but the limit is -2 as y is -2 from the left so \[f(-3)=1,\lim_{x \rightarrow 3^{+}}f=-2\]
so the limit is -2 but the y value is not exisisting there at -2 but it is 1 is that understood
is that x->3 or 2 +?
x-->3+
ah okay thanks. ;)
\[\huge \lim_{x \rightarrow 3^{+}}f=-2\]
\[\huge \lim_{x \rightarrow -3^{-}}f=-2\] in this case the answer is the same as for 3+
is A and B fine
yes! ;)
hold on. A is -> -3+ with negative befpre 3...
i made a typing error there ,you are correct so the 3rd one the remove the signs,for this limit we use the rule that if the left hand limit is the same as right hand limit then the limit is -2
so our answer is -2 for c
got it! ;)
D i already did it above
E for you to make the condition on E work you have to make f(-3)=-2 so that it can work, meaning the shaded dot will be where the empty dot is , exist
got it sir! ;)
i guess you can do 18 by yourself
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