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Mathematics 13 Online
OpenStudy (anonymous):

need help here

OpenStudy (anonymous):

OpenStudy (anonymous):

which one can you do in 17

OpenStudy (anonymous):

nothing ;(

OpenStudy (anonymous):

my prof didnt explain that. ;/

OpenStudy (anonymous):

\[\lim_{x \rightarrow a^{+}}f(x)\] means the limit of f when we come towards a from the right so you will move your hand from the far right towards that a ,for \[a^{-}\] you do the same from the left

OpenStudy (anonymous):

-->

OpenStudy (anonymous):

for \[\lim_{x \rightarrow 3^{+}}\] look at the y value at -3

OpenStudy (anonymous):

when x=-3 , y=?

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

-2

OpenStudy (anonymous):

yes notice that it is not shaded so y=1 where it is shaded but the limit is -2 as y is -2 from the left so \[f(-3)=1,\lim_{x \rightarrow 3^{+}}f=-2\]

OpenStudy (anonymous):

so the limit is -2 but the y value is not exisisting there at -2 but it is 1 is that understood

OpenStudy (anonymous):

is that x->3 or 2 +?

OpenStudy (anonymous):

x-->3+

OpenStudy (anonymous):

ah okay thanks. ;)

OpenStudy (anonymous):

\[\huge \lim_{x \rightarrow 3^{+}}f=-2\]

OpenStudy (anonymous):

\[\huge \lim_{x \rightarrow -3^{-}}f=-2\] in this case the answer is the same as for 3+

OpenStudy (anonymous):

is A and B fine

OpenStudy (anonymous):

yes! ;)

OpenStudy (anonymous):

hold on. A is -> -3+ with negative befpre 3...

OpenStudy (anonymous):

i made a typing error there ,you are correct so the 3rd one the remove the signs,for this limit we use the rule that if the left hand limit is the same as right hand limit then the limit is -2

OpenStudy (anonymous):

so our answer is -2 for c

OpenStudy (anonymous):

got it! ;)

OpenStudy (anonymous):

D i already did it above

OpenStudy (anonymous):

E for you to make the condition on E work you have to make f(-3)=-2 so that it can work, meaning the shaded dot will be where the empty dot is , exist

OpenStudy (anonymous):

got it sir! ;)

OpenStudy (anonymous):

i guess you can do 18 by yourself

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