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OpenStudy (anonymous):
what is the lcm of -14a^3b^7 and 21a^5b^2
OpenStudy (anonymous):
isit 7a^8b^9
jimthompson5910 (jim_thompson5910):
what's the LCM of 14 and 21
OpenStudy (anonymous):
42
OpenStudy (anonymous):
for the coefficent - LCM multiply the coefficient - what is the smallest number
that both 14 and 21 divide evenly.
So look at x^3 and x^5; Do you see that x^5 is the smallest monomial that
both x^3 and x^5 divide evenly?
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And looking at b^7 and b^2; Do you see that b^7 is the smallest?
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jimthompson5910 (jim_thompson5910):
now find the LCM of a^3 and a^5
OpenStudy (anonymous):
wait do I divide 3 and 5
jimthompson5910 (jim_thompson5910):
you just take the larger exponent
so the LCM is a^5
jimthompson5910 (jim_thompson5910):
the LCM of b^2 and b^7 is b^7
jimthompson5910 (jim_thompson5910):
all together:
LCM of -14a^3b^7 and 21a^5b^2 is 42a^5b^7
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OpenStudy (anonymous):
are you sure there is not that answer
jimthompson5910 (jim_thompson5910):
what answer choices do you have
OpenStudy (anonymous):
here is what I have
7a^8b^9
249a^8b^9
249a^3b^2
7a^3b^2
jimthompson5910 (jim_thompson5910):
looks like you want the GCF (and not the LCM) then
jimthompson5910 (jim_thompson5910):
I see the GCF in there, but not the LCM
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OpenStudy (anonymous):
agreed with Jim :)
OpenStudy (anonymous):
oh yeah sorry guys
OpenStudy (anonymous):
your answer for the 7 is correct, but for GCF and exponents; you take the smaller of the exponents
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so it would be 7a^3b^2
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