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Mathematics 7 Online
OpenStudy (anonymous):

Hey you guys I REALLY NEED HELP

OpenStudy (anonymous):

what is the lcm of -14a^3b^7 and 21a^5b^2

OpenStudy (anonymous):

isit 7a^8b^9

jimthompson5910 (jim_thompson5910):

what's the LCM of 14 and 21

OpenStudy (anonymous):

42

OpenStudy (anonymous):

for the coefficent - LCM multiply the coefficient - what is the smallest number that both 14 and 21 divide evenly. So look at x^3 and x^5; Do you see that x^5 is the smallest monomial that both x^3 and x^5 divide evenly? ----- And looking at b^7 and b^2; Do you see that b^7 is the smallest?

jimthompson5910 (jim_thompson5910):

now find the LCM of a^3 and a^5

OpenStudy (anonymous):

wait do I divide 3 and 5

jimthompson5910 (jim_thompson5910):

you just take the larger exponent so the LCM is a^5

jimthompson5910 (jim_thompson5910):

the LCM of b^2 and b^7 is b^7

jimthompson5910 (jim_thompson5910):

all together: LCM of -14a^3b^7 and 21a^5b^2 is 42a^5b^7

OpenStudy (anonymous):

are you sure there is not that answer

jimthompson5910 (jim_thompson5910):

what answer choices do you have

OpenStudy (anonymous):

here is what I have 7a^8b^9 249a^8b^9 249a^3b^2 7a^3b^2

jimthompson5910 (jim_thompson5910):

looks like you want the GCF (and not the LCM) then

jimthompson5910 (jim_thompson5910):

I see the GCF in there, but not the LCM

OpenStudy (anonymous):

agreed with Jim :)

OpenStudy (anonymous):

oh yeah sorry guys

OpenStudy (anonymous):

your answer for the 7 is correct, but for GCF and exponents; you take the smaller of the exponents

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so it would be 7a^3b^2

OpenStudy (anonymous):

right

jimthompson5910 (jim_thompson5910):

you are correct

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