what is the solution of the system of equations?
2x + 2y + 3z = -6
3x + 5y + 4z = 3
2x + 3y +4z = -10

Question

what is the solution of the system of equations?
 2x + 2y + 3z = -6
3x + 5y + 4z = 3
2x + 3y +4z = -10

anonymous · Answer

Subtract the first equation with the last equation like this:
$$(2x+2y+3z)-(2x+3y+4z)=(-6)-(-10)$$

anonymous · Answer

ohh ok. I can't believe I didn't notice that. I was so focused on the first and second one.

anonymous · Answer

We're not done yet.

anonymous · Answer

You have to multiply the first equation by 3 and then you would have to multiply the second equation by 2.
$$3(2x+2y+3z)=3(-6)$$
$$2(3x+5y+4z)=2(3)$$

anonymous · Answer

Then you subtract to get rid of the x. Then you would have two equations with two variables: y and z.

anonymous · Answer

ok

anonymous · Answer

Then you can go on from there to solve those two new equations like a system.

anonymous · Answer

ok thanks so much for explaining.

anonymous · Answer

No worries.