Question

integrate(xcoshx, x, 0, 1)

Answer 1

\[\int_0^1x\cosh x \;\mathrm dx\]
try integration by parts

Answer 2

I did. But the answer for the integral= (e-1)/e. And I can get that.

Answer 3

*cant

Answer 4

I got to [(1)sinh(1)-(0)sinh(0)]-[cosht]^1(a)0(b)

Answer 5

the 1 and 0 are the a and b for the integration of cosh t

Answer 6

\[\int x\cosh x \mathrm dx=x\sinh x - \cosh x\]
\[\sinh x = (1/2) (e^x - e^{-x})\\\cosh x = (1/2)(e^x+e^{-x})\]

so sinh 1 = (1/2)e^1-e^(-1)