PLS HELP ME Simplify. All variables represent non-negative real numbers. *problem attached
\[c \sqrt{75c} - \sqrt{27c ^{3}}\]
please explain all the steps
Well, when faced with a radical sign, try to factor what's underneath. For example, \(75 = 5*5*3\), so \(\sqrt{75} = \sqrt{5*5*3} = \sqrt{5*5}*\sqrt{3} = 5\sqrt{3}\).
You can similarly factor 27 and c^3.
Try it, report your answer, and I'll check your work.
I honestly don't get it.
What are the factors of 27? What are the factors of c^3?
there's 9 and 3?
and c^2?
Yes, so you can write \(27\) as \(9*3\), and \(c^3\) as \(c^2*c\). How would you simplify those if they were under a square root? Look back at the 75 example.
\[\sqrt{9} * \sqrt{c^2} * \sqrt{3c}\]
which would simplify to \[3c \sqrt{3c}\]
Very good! Now finish up the work on the first term, and combine them for the full answer.
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