Question

lim ((3+h)^5-3^5)/9h
h->0

Answer 1

Expand the denominator. The constants cancel out and then you can get rid of the h on denominator and then you can sub in h=0.

Answer 2

\[(a+b)^5=a^5+5a^4b+10a^3b^2+10a^2b^3+5ab^4+b^5\]

Answer 3

Expand the numerator sorry.**

Answer 4

thank you so much, youve helped so much :D

Answer 5

No worries.