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Physics 4 Online
OpenStudy (anonymous):

A wagon is pulled at a speed of 0.40/s by a horse exerting 1,800 newton horizontal force. what is the power of the horse? power=work x joules work=force times distance

OpenStudy (anonymous):

cool thanks!

OpenStudy (shane_b):

What is " of 0.40/s " supposed to be?

OpenStudy (anonymous):

0.4 meters per second

OpenStudy (anonymous):

this is what it says on my homework sheet. im going in before class tomorrow- i will check then...

OpenStudy (shane_b):

<slaps forehead> Ok, here we go: \[W=F*d\]\[P=\frac{W}{t}=\frac{F*d}{t}=1800N(\frac{0.4m}{1s})=720W\]

OpenStudy (anonymous):

great! why did you multiply it by 1800 N ? 0

OpenStudy (shane_b):

I just pulled the force out to the left to make it more clear...it's the same as:\[P=\frac{W}{t}=\frac{F*d}{t}=\frac{1800N*0.4m}{1s}=720W\]

OpenStudy (anonymous):

thank you so much :) mind doing one more?

OpenStudy (shane_b):

Maybe...let's see it first :)

OpenStudy (anonymous):

IF a small machine does 2500 joules of work to an object to move it a distance of 100 meters in 10 seconds, what is the force needed to do the work? What is the power of the machine doing the work?

OpenStudy (shane_b):

Maybe this will be clearer :) \[2500J=N∗m=F(100m)\]\[F=25N\] Can you do the second part?

OpenStudy (anonymous):

probably not... is it 250 watts? :P

OpenStudy (shane_b):

Yep :)

OpenStudy (shane_b):

Now you're an expert in Work and Power :P

OpenStudy (anonymous):

yay!thank you!

OpenStudy (shane_b):

no problem, good luck!

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