If during take off a 40,000 kg aircraft accelerates at 4 m/s^2, what force is being generated by the engines?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
force=ma
m=mass
a=acceleration
OpenStudy (anonymous):
so whats the answer@cherio
OpenStudy (anonymous):
@cherio12
OpenStudy (anonymous):
40000*4
OpenStudy (anonymous):
ohh okay i had that right can you help me with one more
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
An 80 kg man starts from rest and after 3.50 seconds is running at a speed of 12.0 m/s. The force needed for this man to get up to this speed in 3.50 seconds is ____ N. @cherio12
OpenStudy (anonymous):
vf=vo+at
vf=final velocity (12m/s)
vo=initial velocity (0m/s)
a=acceleration (what you want to find)
t+time (3.5s)
OpenStudy (anonymous):
80*a=F
OpenStudy (anonymous):
so the answer is 80*a=F
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
or is it 80
OpenStudy (anonymous):
80N
OpenStudy (anonymous):
80*a=F
F is the answer you want
OpenStudy (anonymous):
SOO The force needed for this man to get up to this speed in 3.50 seconds is __F__ N
OpenStudy (anonymous):
well yes..but you need to plug in the values
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
HOW DO I DO THAT
OpenStudy (anonymous):
I showed you all the values and where they go in an earlier post
OpenStudy (anonymous):
YEA I KNO BUT HOW DO I SOLVE IT DO I MULTIPLY
OpenStudy (anonymous):
12=a*3.5
a*80=F
OpenStudy (anonymous):
a=3.4286
Still Need Help?
Join the QuestionCove community and study together with friends!