OpenStudy (anonymous):

How do you being to factor this equation? (x^2+2)(a+3)+(x^2+2)(2a+7) Thank you!

4 years ago
OpenStudy (anonymous):

you mean foil? because this equation is already factored...

4 years ago
OpenStudy (anonymous):

or do you mean refactor into a product of two single expressions?

4 years ago
OpenStudy (anonymous):

The directions simply say factor. Should I start off foiling then go from there, or would I factor out the GCF (x^2+2) first?

4 years ago
OpenStudy (anonymous):

lol definitely do that

4 years ago
OpenStudy (anonymous):

then sum like terms

4 years ago
OpenStudy (anonymous):

(x^2+2)(3a+10)

4 years ago
OpenStudy (anonymous):

Thank you, I understand how to do the problem now. Thank you very much!

4 years ago
OpenStudy (anonymous):

Np!, you pretty much solved it yourself :D

4 years ago
OpenStudy (anonymous):

(x^(2)+2)(a+3)+(x^(2)+2)(2a+7) Factor out the GCF of (x^(2)+2) from each term in the polynomial. (x^(2)+2)((a+3))+(x^(2)+2)((2a+7)) Factor out the GCF of (x^(2)+2) from (x^(2)+2)(a+3)+(x^(2)+2)(2a+7). (x^(2)+2)((a+3)+(2a+7)) Remove the parentheses that are not needed from the expression. (x^(2)+2)(a+3+2a+7) Since a and 2a are like terms, add 2a to a to get 3a. (x^(2)+2)(3a+3+7) Add 7 to 3 to get 10. (x^(2)+2)(3a+10)

4 years ago