Question

how do I find the derivative of f(x)= sin[ln(cosx^3)]

Answer 1

Use chain rule here
\[\frac{d}{dx} f( g(x))=f'(x)\times \frac{d}{dx} g(x)\]
Could you try ?

Answer 2

would it be cos[lncosx^3] X (-sinx^3)/(cosx^3) ?

Answer 3

times the derivative of x^3
\[\cos (\ln{\cos x^3})\times \frac{1}{\cos x^3}\times (-\sin x^3)\times \frac{d}{dx} (x^3)\]
Good work btw

Answer 4

Thanks !

Answer 5

You're welcome :D