Ask your own question, for FREE!
Mathematics 5 Online
OpenStudy (anonymous):

CHECK MY WORK

OpenStudy (nincompoop):

correct!

OpenStudy (anonymous):

|dw:1359436205915:dw|

OpenStudy (anonymous):

Does that say x is less than 1?

OpenStudy (anonymous):

|dw:1359436614514:dw|

OpenStudy (anonymous):

?

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (whpalmer4):

Are you saying that if \[\frac{(2x+1)}{(x+1)} \le 2\] then \[x \le 1\]?

OpenStudy (anonymous):

so im right?

OpenStudy (anonymous):

wait no my answer is x<1

OpenStudy (nincompoop):

show your step-by-step solution

OpenStudy (whpalmer4):

How about if x = -2? (2(-2)+1)/(-2+1) = -3/-1 = 3, oops.

OpenStudy (anonymous):

@whpalmer4 , no thats not a answer choice.

OpenStudy (whpalmer4):

My point is that x = -2 is a value that should work if your answer is correct. It doesn't. Therefore, your answer is not correct.

OpenStudy (anonymous):

so \[x \ge -1\]

OpenStudy (nincompoop):

SHOW YOUR SOLUTION :)

OpenStudy (whpalmer4):

You're clearly just guessing at a list of answers. If you are going to do that, you need to check your guesses!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!