OpenStudy (anonymous):

Simplify: 1/(7x)-1/(5x) and Find a solution: 1/9x+1/10=11/90 please and thank you.

5 years ago
OpenStudy (whpalmer4):

$\frac{1}{7x}-\frac{1}{5x}$Find a common denominator, then combine. Do you know how to do that?

5 years ago
OpenStudy (anonymous):

I think so. Thank you.

5 years ago
OpenStudy (whpalmer4):

For the other one, the same approach is appropriate. Find a common denominator, or multiply the whole equation by the product of all of the denominators.

5 years ago
OpenStudy (anonymous):

is it 2/35?

5 years ago
OpenStudy (whpalmer4):

There better be an x in there somewhere, don't you think?

5 years ago
OpenStudy (anonymous):

Yes there is. Thank you again.

5 years ago
OpenStudy (anonymous):

(1)/(7x)-(1)/(5x) To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 35x. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. (1)/(7x)*(5)/(5)-(1)/(5x)*(7)/(7) Multiply 1 by 5 to get 5. (5)/(5*7x)-(1)/(5x)*(7)/(7) Multiply 7x by 5 to get 35x. (5)/(35x)-(1)/(5x)*(7)/(7) Multiply -1 by 7 to get -7. (5)/(35x)-(7)/(7*5x) Multiply 5x by 7 to get 35x. (5)/(35x)-(7)/(35x) Combine the numerators of all expressions that have common denominators. (5-7)/(35x) Subtract 7 from 5 to get -2. (-2)/(35x) Move the minus sign from the numerator to the front of the expression. -2/35x

5 years ago
OpenStudy (whpalmer4):

Agree with -2/35x.

5 years ago
OpenStudy (anonymous):

(1)/(9)*x+(1)/(10)=(11)/(90) Multiply 1 by x to get x. (x)/(9)+(1)/(10)=(11)/(90) Since (1)/(10) does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting (1)/(10) from both sides. (x)/(9)=-(1)/(10)+(11)/(90) To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 90. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. (x)/(9)=(11)/(90)-(1)/(10)*(9)/(9) Multiply -1 by 9 to get -9. (x)/(9)=(11)/(90)-(9)/(9*10) Multiply 10 by 9 to get 90. (x)/(9)=(11)/(90)-(9)/(90) Combine the numerators of all fractions that have common denominators. (x)/(9)=(11-9)/(90) Subtract 9 from 11 to get 2. (x)/(9)=(2)/(90) Cancel the common factor of 2 the expression (2)/(90). (x)/(9)=(<X>2<x>)/(45<X>90<x>) Remove the common factors that were cancelled out. (x)/(9)=(1)/(45) Multiply each term in the equation by 9. (x)/(9)*9=(1)/(45)*9 Cancel the common factor of 9 in the denominator of the first term (x)/(9) and the second term 9. (x)/(<X>9<x>)*<X>9<x>=(1)/(45)*9 Reduce the expression by removing the common factor of 9 in the denominator of the first term (x)/(9) and the second term 9. x*1=(1)/(45)*9 Multiply x by 1 to get x. x=(1)/(45)*9 Cancel the common factor of 9 in the denominator of the first term (1)/(45) and the second term 9. x=(1)/(5<X>45<x>)*<X>9<x> Reduce the expression by removing the common factor of 9 in the denominator of the first term (1)/(45) and the second term 9. x=(1)/(5)*1 Multiply 1 by 1 to get 1. x=(1)/(5)

5 years ago
OpenStudy (anonymous):

can you please draw it for me? Thank you.

5 years ago
OpenStudy (whpalmer4):

Is the problem $\frac{1}{9x} + ...$ or $\frac{1}{9}x + ...$?

5 years ago
OpenStudy (anonymous):

|dw:1359439362873:dw| this is the problem.

5 years ago