OpenStudy (anonymous):

sum [k=2, inf] (1-2^(k+1)) / 3^k

5 years ago
OpenStudy (anonymous):

\[\sum_{k=2}^{\infty} \frac{ 1-2^{k+1} }{ 3^{k} }\]

5 years ago
OpenStudy (anonymous):

Its limit?

5 years ago
OpenStudy (shubhamsrg):

Split it into (1/3)^k - 2.(2/3)^k Thus you'll get 2 infinite GPs. Are you following ?

5 years ago
OpenStudy (anonymous):

I'm following but how do I proceed?

5 years ago
OpenStudy (anonymous):

|dw:1359444693644:dw|

5 years ago
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