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Mathematics 8 Online
OpenStudy (anonymous):

Check my work: Arc Lengths

OpenStudy (anonymous):

OpenStudy (anonymous):

Derivative of x^3/3 + 1/4x^2 = x^2 -1/4x^2 Derivative squared:x^4 + 1/16x^4 -1/2

OpenStudy (anonymous):

Derivative squared +1: x^4 + 1/16x^4 -1/2 + 1 = x^4 + 1/16x^4 +1/2 Square root: sqrt( x^4 + 1/16x^4 +1/2) = x^2 +1/4x^2 + 1/sqrt(2)

OpenStudy (anonymous):

correct process.

OpenStudy (anonymous):

\[\int\limits_{1}^{2} x^2 +1/4x^2 + 1/\sqrt(2) = 59/24+1/\sqrt(2)\]

OpenStudy (anonymous):

answer is correct.

OpenStudy (anonymous):

Problem is, the answer is just 59/24.

OpenStudy (anonymous):

!!!

OpenStudy (anonymous):

I don't see how I got that 1/sqrt(2) part wrong. My mathbook says it's just 59/24.

OpenStudy (anonymous):

second part may be missing fm book. May be printing mistake.

OpenStudy (anonymous):

@sirm3d , do you see what I did wrong?

OpenStudy (sirm3d):

i'm still checking.

OpenStudy (anonymous):

Thanks!

OpenStudy (sirm3d):

\[\sqrt{x^4-\frac{1}{2}+\frac{1}{16x^4}+1}=\sqrt{x^4+\frac{1}{2}+\frac{1}{16x^4}}=x^2+\frac{1}{4x^2}\]

OpenStudy (sirm3d):

\[\Large L=\int_1^2 x^2+\frac{1}{4x^2} \;\mathrm dx\]

OpenStudy (anonymous):

Okay, that makes sense. Thanks!

OpenStudy (sirm3d):

yw

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