Question

A hailstone traveling with a velocity of 43 meters/second comes to a virtual stop 0.28 seconds after hitting water. What is the magnitude of its acceleration in the water?

Answer 1

use $$v=u+at$$

Answer 2

Acceleration is the change in velocity divided by time.

So

\[\frac{ Vf - Vi }{ T }\]

Vf = 0 and Vi = 43
and T = .28s

So

\[a = \frac{ 0 - 43 }{ .28 }\]