Question

Can someone help me with this..

2y''+7y'+3y+0 .: y'(0)=0, y(0)=3

Answer 1

Have you considered the Characteristic Equation?

Answer 2

2y''+7y'+3y=0 .: y'(0)=0, y(0)=3...

Answer 3

@ apad12
is ur question
2y''+7y'+3y=0

Answer 4

So, then that's a "no".

Given such a problem statement, you should have seen this associated equation, the Characteristic Equation:

\(2r^{2} + 7r + 4 = 0\)

Your first task is to solve this equation. It is easier if you can factor the LHS.

Answer 5

then the characteristic equation is
2m^2 +7m +3 =0 where y=e^(mx) is a trial solution

2m^2 +6m+1m +3=0
2m(m+3)+1(m+3)=0
(m+3)(2m+1)=0
hence m=-3,-0.5
hence y=Ae^(-3x) + Be^(-0.5x)