Question

Suppose that we know..
∫1,10(3k(x)+5)dx=66

What is the value of..
∫1,10k(x)dx

Answer 1

What's your question?...

Answer 2

Is 1,10 corresponding with a,b or b,a?

Answer 3

a,b

Answer 4

\[\int\limits_{1}^{10}(3kx+5)dx=\frac{ 3k }{ 2 }x^2+5x\]
\[[\frac{ 3k }{ 2 }(10)^2+5(10)]-[\frac{ 3k }{ 2 }(1)^2+5(1)]=150k+50-\frac{ 3k }{ 2 }-5\]
\[=\frac{297}{2}k+45\]
\[\frac{297}{2}k+45=66\]
\[k=\frac{14}{99}\]
\[\int\limits_{1}^{10}(kx)dx=\frac{k}{2}x^2\]
\[\frac{7}{99}(10)^2-\frac{7}{99}(1)^2=\frac{700}{99}-\frac{7}{99}\]
\[=7\]

Answer 5

I just started learning integrals. Can't believe I solved it for you...

Answer 6

Thank you so much