cant remember how to do
multiply
(x+8)6x and (x+8)(x-2)

Question

cant remember how to do
multiply
(x+8)6x    and (x+8)(x-2)

anonymous · Answer

$$a(b+c)=ab+ac$$ distrubutive property of equalities

mathstudent55 · Answer

The distributive property will help:
(a + b)c = c(a + b) = ca + cb
(x + 6)6x = 6x(x + 6) = 6x(x) + (6x)(6)
Now do those two multiplications.

anonymous · Answer

so it would be 6x^2+48=84

anonymous · Answer

which is the same because
$$(a+b)c=ac+bc=ca+cb=c(a+b)$$

anonymous · Answer

=]

anonymous · Answer

that only works for the first... the second is a method known as foiling

$$(a\pm b)(c\pm d)=ac\pm ad\pm bc \pm bd$$

mathstudent55 · Answer

6x(x + 8) = 6x(x) + (6x)(8) = 6x^2 + 48x That's it.
Unlike terms can't be added together.
Unlike terms are terms that have different variable parts. 
x^2 and x are different variable parts.

anonymous · Answer

so 27x for the swcond?

mathstudent55 · Answer

Second one is the product of two binomials where you use FOIL to do it. Are you familiar with FOIL?

anonymous · Answer

if this helps you can also use the distributive

$$(a\pm b)(c \pm d)=a(c\pm d)\pm b(c\pm d)
$$by distributive

anonymous · Answer

which is the same as what i put above

anonymous · Answer

im not familiar to FOIL

mathstudent55 · Answer

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