find all the currents and the potential differences in the following circuit using Kirchhoff Rules

Question

anonymous · Answer

i'll attach the paper soon :)

anonymous · Answer

@ajprincess  @ghazi  @shubhamsrg

anonymous · Answer

attachment

anonymous · Answer

i have already tried but my equations are unsolvable :(  should i attach my work too?

vincent-lyon.fr · Answer

Call i1 current in top loop and i2 current in bottom loop and write the 2 loop equations.
Then we'll see what goes wrong.

anonymous · Answer

@Vincent-Lyon.Fr  sorry am back :)

anonymous · Answer

ok so i keep the same direction?

vincent-lyon.fr · Answer

Keep the anti-clockwise direction for instance.

anonymous · Answer

ok

anonymous · Answer

but we are going clockwise according to the arrow..

anonymous · Answer

this is what i did, i named A and B junction points..
A) I3+I2-I1
B)I1-I2-I3
is that correct so far?

vincent-lyon.fr · Answer

Yes, but this is just another way of writing i3 = i1 - i2

Write $\Sigma$ (potential differences) = 0 is each loop.

vincent-lyon.fr · Answer

Sorry, go clockwise!

anonymous · Answer

ok then our loop equation then are the following:
1) U+I1R6-U2-I1R1-I3R3=0
5+3I1-3-5I3-4I1=0
2) I2(R2+R4+R5)+I3R3=0
9I2+5I3=0

anonymous · Answer

its ok, i'll just leave it and review other things :) thank you for the help though

vincent-lyon.fr · Answer

No, within a loop, the sign before any $R_n\;i_{loop}$ will always be the same.

Loop 1 must go:

$4i_1-5+3i_1+3+5(i_1-i_2)=0$

vincent-lyon.fr · Answer

Loop 2 is:

$6i_2+1i_2+2i_2+5(i_2-i_1)=0$