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Find a solution of the intial value problem. dy/dx = (e^(x-y))/(1+e^x), y(1)=0
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well did you try variable separation method?
I did, and not sure if I am right. But i am at. y = ln | ln | 1 + e^x | + c | but it looks wrong to me
hint :\[\large e^{x-y}=\dfrac{e^x}{e^y}\]
you are right !! :)
now use y(1) to get c
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what I got was right... okay, so then I would just plug in the 0 and 1 and find c
0 = ln | ln | 2 + e^1 | + C |
umm 0 = ln |2 + e^1| + C how do I find C, or do I just make it a decimal
C=-ln|2+e|
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