Question

Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).

y = one thirdx + 7

y = −3x + 3

y = one thirdx + 3

y = −3x + 7

Answer 1

y = −3x + 12
can you find the slope of this line??

Answer 2

???

Answer 3

y = mx + b

Answer 4

yes here m is the slope now tell me the slope from the given equation

Answer 5

-3?

Answer 6

exactly

Answer 7

now when two lines are parallel their slopes are equal thus you got the slope for your line
which is???

Answer 8

-3

Answer 9

yes now you have slope = m = -3
and one point (-1,6)
use point slope from to get the equation

Answer 10

point slope form is
y-y1 =m(x-x1)

Answer 11

Im confused...

Answer 12

ok look here

Answer 13

you have slope = -3 right
and one point mentioned in your question
(-1,6) right???

Answer 14

yea

Answer 15

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Answer 16

using point slope form to get the equation
y-y1 =m(x-x1) is a point slope form of line
here y1 =6
x1 = -1
and m = -3
can you find the equation now???

Answer 17

-1 = -18

Answer 18

?

Answer 19

no no

Answer 20

we have
y-y1 =m(x-x1)
y-6 =-3(x-(-1))
y-6 = -3(x+1)
do it further

Answer 21

y - 6 = -3x + -3

Answer 22

add 6 to both sides what you get???

Answer 23

3

Answer 24

y = -3x+3
is your answer

Answer 25

Yay! Thank you!

Answer 26

welcome