Ask
your own question, for FREE!
Mathematics
4 Online
OpenStudy (anonymous):
If ABC is a triangle with AB=20,BC=22 and CA=24. Let D lie on BC such that AD is the angle bisector of ∠BAC.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
find \[AB^2\]
OpenStudy (anonymous):
is an angle bisector also a side bisector
OpenStudy (anonymous):
ie in a triangle
OpenStudy (anonymous):
@satellite73 @shubhamsrg @phi
OpenStudy (phi):
in general, no the angle bisector does not bisect the opposite side
(It does if you had an isosceles triangle)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (phi):
what are you trying to find ?
OpenStudy (anonymous):
AB^2
OpenStudy (phi):
Does AB mean length of side AB ? Because they give you that, and you just square it.
OpenStudy (anonymous):
sorry AD^2
OpenStudy (phi):
This looks painful
One way is to use the law of cosines and find all three angles A, B, and C of the triangle.
Can you do that ?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (phi):
once you have the 3 angles we can take the next step.
OpenStudy (anonymous):
wat i did so far
\[x^2=AD^2+24^2-2AB24\cos \theta\]
\[(22-x)^2=AD^2+20^2-2AD20\cos \theta\]
\[22^2=24^2+20^2-2(24)(20)\cos 2\theta\]
OpenStudy (anonymous):
|dw:1359757929965:dw|
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!