Integral of e^(5t+pi)
ntegral by sub.. let u=5t+pi du = 5 dt or dt = du/5 so, the integration can be : int e^(5t+pi) dt (i assumed it respect to dt) =1/5 * int e^u du = ...
just remember the formula int e^x = e^x too
=1/5*int t e^u du ... and then I used Integration by Parts? I got (1/5 e^(5t+pi))(t-1) + c Is this right?
here, we neednt use int by parts, but it is integration by substitution ...
Yes, I used int by sub first. Then, I used parts.
1/5 * int e^u du = 1/5 * e^u + c subt back that u=5t+pi , therefore = 1/5*(e^5t+pi ) + c
hmm..typo = 1/5*e^(5t+pi ) + c
Sorry! I didn't give you the rest of the problem. That's why I am confused. Integral of t * e^(5t + pi) dt
=1/5*int t e^u du ... and then I used Integration by Parts? I got (1/5 e^(5t+pi))(t-1) + c Thank you so much for helping me.
Oooooo ....~0.0~
Sorry about that. I asked you for just the e^ part and then the problem had an extra (t) in it!! Thank you for helping me!!
nevermind... im a true helper :) well, we need int by part |dw:1359592010581:dw|
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