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Mathematics 6 Online
OpenStudy (anonymous):

help ( attached below)

OpenStudy (anonymous):

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

@usccarolinagurl @ariellynn1 @amistre64 @ajprincess @KonradZuse

Directrix (directrix):

The y-intercept is where the graph cuts the y-axis. Read that point from the graph and post here. Then, we'll have to figure the slope.

OpenStudy (anonymous):

-3

Directrix (directrix):

Okay. We'll use the slope-intercept form of the equation of a line: y = mx + b where b is the y-intercept and m is the slope.

Directrix (directrix):

So far, we have y = mx -3. One way to think about slope is the change in y over the change in x. @elexusvanderhorst How have you been computing slope? We'll do what you already know although I'm thinking we can read the slope off the graph. Tell me what you think.

OpenStudy (anonymous):

ive always been confused on how to do slope

Directrix (directrix):

We'll read it from this graph. I'll post a diagram shortly. Before that, recall that slope has to do with the rate of change of y with respect to x. If the slope of a line is 5 over 7, then that means every time x moves 7 units to the right, the corresponding value of y moves up 5 units.

Directrix (directrix):

For a line, slope is constant. In this problem, as x moves 2 to the right, y goes up by 1. So, the slope is 1/2. So, what is the equation of the line in y = mx + b form? Recall that you already found the intercept (So far, we have y = mx -3) .

Directrix (directrix):

Look at the diagram for a "picture" of slope.

OpenStudy (anonymous):

y=1/2x-3

OpenStudy (anonymous):

omg dude I <3 ur pic

OpenStudy (anonymous):

me?

OpenStudy (anonymous):

@alahrichi1 thanks i love one direction

OpenStudy (anonymous):

no santa claus

OpenStudy (anonymous):

me 2 fanned u becuz of it

OpenStudy (anonymous):

lol thanks

Directrix (directrix):

@elexusvanderhorst yes for y=1/2x-3. I might write it as y = (1/2) x - 3. I <3 ur pic --> I thought she was talking about my diagram.

OpenStudy (anonymous):

@Directrix thank you for your help

Directrix (directrix):

Glad to help.

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