Question

dy/dx=x+1/y+1

Answer 1

what is your question?

Answer 2

solve differntially

Answer 3

\[\large \frac{dy}{dx}=\frac{x+1}{y+1}\]"multiply" the dx to the other side.\[\large dy=\frac{x+1}{y+1}dx\]multiply the y+1 to the the other side,\[\large (y+1)dy=(x+1)dx\]

Answer 4

From here we can integrate! :)

Answer 5

im following you.

Answer 6

\[\large \int\limits(y+1)dy=\int\limits(x+1)dx\]Giving us,\[\large \frac{1}{2}y^2+y+c_1=\frac{1}{2}x^2+x+c_2\]

Answer 7

We can subtract c1 to the other side, and simply combine the constants and label it as some new arbitrary constant.\[\large \frac{1}{2}y^2+y=\frac{1}{2}x^2+x+C\]

Answer 8

Hopefully that part makes sense :o

Answer 9

http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427eivp3ea9t60

Answer 10

Woops tom, you need to use brackets when you put things into wolfram, it's very fussy about that.

Answer 11

i spotted that too. thanks zep. got real confused once i got down to c1 and c2. thanks for the help! stick around i got some more differential equations homework if your interested

Answer 12

heh k. Just throw a @zepdrix into your thread somewhere if you can't find me.