Question

I need help!!!

Answer 1

okay well the theorem is \[z^2=x^2+y^2\] and you know everything has to be an integer (whole number)

Answer 2

you can just try different values. For instance for the first one i might try z=51 and x=24. so 51^2=24^2+y^2. Solving i get y=45. So this works

Answer 3

can you try 19?

Answer 4

@cherio12 can you try #19 plz

Answer 5

you just have to play with the numbers. I first tried \[z^2=25^2+20^\] but i got z= 32.0156..so this didn't work
next i tried
\[25^2=20^2+y^2\]
y=15 (this is an integer) so it checks out

Answer 6

does this make sense?

Answer 7

thats the answer in the book so i should be able to learn off your 2 answers

Answer 8

wait so on 18# i got 2601=576+y2 then do i get y by itself? @cherio12

Answer 9

yes. you should go 2601-576=y^2. then take the squareroot of both sides to just get y

Answer 10

ok how do you know were to put the numbers on the equation?

Answer 11

what do you mean?

Answer 12

wait oh i see you said move them around and it has to be a whole number

Answer 13

yup, its always (leg)^2+(leg)^2=(hypotenuse)^2

Answer 14

thanks man! helped alot

Answer 15

its commonly written as x^2+y^2=z^2

Answer 16

no problem =D

Answer 17

k

Answer 18

wait so on # 20 i got 91.82592222ect

Answer 19

okay so that means you picked the wrong combo of hypotenuse and legs. try another combo (by the way the hypotenuse will always be the largest of the 3 numbers)

Answer 20

so set it up as x2= 96 + 28?

Answer 21

i would try
\[96^2=x^2+28^2\]

Answer 22

do get x by its self?

Answer 23

yes

Answer 24

but i still will get that 91.etc right?

Answer 25

i was just showing you the triangle to help show what i meant by x, y and z

Answer 26

i know im saying when i get x by its self and take 9216 and square it i get that 91.00202 number

Answer 27

o you mean for the 96, 28 problem?

Answer 28

yes

Answer 29

\[96^2=x^2+28^2\]
\[9216=x^2+784\]
\[9216-784=x^2\]
\[x=\sqrt{8432}\]
x=91.8259
so this way didn't work.

Answer 30

i would then try \[z^2=96^2+28^2\]

Answer 31

but you would still get 91.8259 right?

Answer 32

no i got 100

Answer 33

you add 96^2 and 28^2 in this example instead of subtracting them (like we tried before)

Answer 34

ohhh

Answer 35

now i see thakns agian lol

Answer 36

hey can you help @cherio12 with # 23

Answer 37

sure

Answer 38

okay so i first tried z^2=72^2+75^2
But i got z=103.966 so that's not right
then i tried 75^2=x^2+72^2

Answer 39

ok i did the first but didnt try that one what did you get?

Answer 40

21

Answer 41

can you show how you did that?

Answer 42

75^2=x^2+72^2
solve for x

Answer 43

ok thanks i got 21

Answer 44

no problem

Answer 45

hey @cherio12 for #24 you you do the same?

Answer 46

yes, your two legs are 6 and 3

Answer 47

so would it be 6(2)=3(2)+x2

Answer 48

@cherio12

Answer 49

by(2) do you mean you are squaring it?

Answer 50

no 6 to the power 2 like 6*6

Answer 51

that means squaring, but yes that is correct