Question

help me please Algebra 1

Answer 1

2\[(-2)^{-3*24}=(-2)^{72}\]

Answer 2

I think that should be
\[(-m)^{-3}n\]
Yes?

Answer 3

what exactly is your question, what are you supposed to find?

Answer 4

First thing to remember is that \[x^{-m} = \frac{1}{x^m}\]If we rewrite the expression in that fashion, we get \[\frac{n}{(-m)^3} = \frac{-24}{(-2)^3}\]Can you evaluate that?

Answer 5

\[(-2)^3 = (-2)*(-2)*(-2)\]

Answer 6

well no

Answer 7

its negative though right?

Answer 8

its -3 right?

Answer 9

@ghazi what do you mean, "well no"?

Answer 10

he means its not -4

Answer 11

Did someone say it was?

\[\frac{-24}{(-2)*(-2)*(-2)}\]What does the expression on the bottom equal?

Answer 12

its not -4 , its 4 ,if the explanation of @whpalmer4 is true and second i am not sure if that explanation is true, it would be great if you could take snapshot and post it here :D @carlenstar281

Answer 13

I cant but thank you for helping me :)

Answer 14

:) YW

Answer 15

Yes, all of my statements are true and correct. The answer is not 4.

Answer 16

are you sure i get 4?

Answer 17

What is -2 * -2 * -2?

Answer 18

\[\frac{ -24 }{ -2*-2*-2 }=\frac{ -24 }{ -8 }---> -A*-A*-A=-A\]

Answer 19

and \[\frac{ -24 }{ -8 }=\frac{ 24 }{ 8 }=3\] LOL

Answer 20

that was the silliest mistake i've ever done

Answer 21

sorry computer froze haha its okay i did that to still thanks for helping!

Answer 22

np :)

Answer 23

also thank you to @whpalmer4 as well haha

Answer 24

Another way of looking at this is \[\frac{-24}{(-1*2)^3} = \frac{-24}{(-1)^3*2^3}\]\(-1^n = -1, n\) odd so we have
\[\frac{-24}{-1*2^3} = \frac{-24}{-8} = 3\]

Answer 25

We can factor out that -1 because \[(ab)^n = a^nb^n\]