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evaluate each expression: Logs. Click 2 see.
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\[\log _{\sqrt{8}}4096\]
is that sqrt{8} or {3}
8
\[\huge \log _{\sqrt{8}}{4096}=\log_{8^{1/2} }4096\] use change of base rule\[\huge \log _ba=\frac{\log a}{\log b}\]
okay . and then simplify that ?
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yes
okay then?
you mean take 4096 and divide it by 8^1/2 ?
yes but both preceded by log
4096=64^2 \[\huge \frac{\log 4096}{\log 8^{1/2}}\]
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i got 4 ?
@Jonask
\[\huge \frac{4\log 8}{\log 8}=4\]
yes
but the back of my book has the answer as: 8 ?
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i forgot the half also it is supposed to be dropped\[\huge \frac{4 \log 8}{1/2\log 8}=4\div{1/2}=8\]
OH okay . thanks :)
yw
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