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solve each equation: logs, click to see.
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\[\log _{12}x=\frac{ 1 }{ 2 }\log _{12}9+\frac{ 1 }{ 3 }\log _{12}27\]
\[\frac{ 1 }{ 6 }\log_{12}x = \log_{12} (27\times9) next step \frac{ 1 }{ 6 }\log_{12}x =243\]
wait steap 2 should be add log12 front of 243
so log12x 243?
cancel log12 from both side \[\frac{ 1 }{ 6 }x= 243 do the rest\]
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you right
log sub 12 ?
or just log 12 in general?
okay , i canceled it . then ?
ok
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i have to find what times 1/2 = 243 right ?
does x = 1458?
@slimfit
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