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Mathematics 20 Online
OpenStudy (anonymous):

solve each equation: logs, click to see.

OpenStudy (anonymous):

\[\log _{12}x=\frac{ 1 }{ 2 }\log _{12}9+\frac{ 1 }{ 3 }\log _{12}27\]

OpenStudy (anonymous):

\[\frac{ 1 }{ 6 }\log_{12}x = \log_{12} (27\times9) next step \frac{ 1 }{ 6 }\log_{12}x =243\]

OpenStudy (anonymous):

wait steap 2 should be add log12 front of 243

OpenStudy (anonymous):

so log12x 243?

OpenStudy (anonymous):

cancel log12 from both side \[\frac{ 1 }{ 6 }x= 243 do the rest\]

OpenStudy (anonymous):

you right

OpenStudy (anonymous):

log sub 12 ?

OpenStudy (anonymous):

or just log 12 in general?

OpenStudy (anonymous):

okay , i canceled it . then ?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i have to find what times 1/2 = 243 right ?

OpenStudy (anonymous):

does x = 1458?

OpenStudy (anonymous):

@slimfit

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