How many different 7-letter arrangements are there of the letters in ALGEBRA?

Question

directrix · Answer

There are 7 choices for the first letter, 6 for the second, and so on to 1 choice for the 7th letter.
That would yield 7*6*5*4*3*2*1 = ? non-distinct arrangements (permutations).
Get that product. --> Product
Then, because the letter "A" appears twice in AlGEBRA, some of the 7 letter arrangements have been repeated.
So divide the product by 2 to get the number of distinct 7-letter arrangements of the letters of the word ALGEBRA.

Post your answer.

anonymous · Answer

7! = 5040

directrix · Answer

@KHatrak 

Remember to divide 7! by 2 to get the number of distinct 7-letter permutations.
7! is not the correct answer to the question.

anonymous · Answer

@Directrix would it be 7*6*5*4*3*2!/2 = 2520?

directrix · Answer

@KHatrak  That's what I got.