Question

If x is the smallest integer, which of the following equations models the problem? I got X+(x+2)+(x+4)+(x+6)=636. Is this correct? Please and thank you.

Answer 1

there is no smallest integer

Answer 2

so they are all true

Answer 3

So it would none of the above?

Answer 4

if you are doing if then -> -p ^ q

Answer 5

@What is the problem being modeled?

x appears to be 156 on what was posted but what is the scenario of the problem that calls for the smallest x?

@kitsune0724

Answer 6

they are all true

Answer 7

The question just says if x is the smallest integer, which of the equations models the problem. The choices are: 4x=636, x(x+2)(x+4)(x+6)=636, x+(x+2)+(x+4)+(x+6)=636, x+(x+2)+(x+4)+(x+6)=636 and none of the above. I got the third choice. @Directix

Answer 8

@Directrix

Answer 9

@kitsune0724 I assume that we have to solve all the equations for x and then choose as the answer the equation which yields the smallest value of x of all options. Let me check your answer.

Answer 10

@kitsune0724 In the options, I think you wrote one of them twice:
x+(x+2)+(x+4)+(x+6)=636, x+(x+2)+(x+4)+(x+6)=636.

What is supposed to be there?

Answer 11

how is there a smallest integer? I think this is a question about if then....which is -P v Q thus since P is false the statement is true for what follows...

Answer 12

Something bothers me about this problem. The question asks the following: " which of the equations **models the problem.**

@kitsune0724 --> What problem?

Answer 13

yes. it's suppose to be there. @Directrix

Answer 14

That's all it says in the problem.

Answer 15

plewase tell me why you guys are ignoring the smallest integer part? and my explination...

Answer 16

I'm not ignoring your explanation @zzr0ck3r but that's not one of the choices.

Answer 17

hehe, they are all true is the choice:)

Answer 18

@zzr0ck3r -P v Q thus since P is false the statement is true for what follows...
I am not commenting on your contributions because I do not follow what they have to do with the problem.

And, I STILL do not think we have been given the entire problem.
My best guess is that there's a given problem about consecutive integers and we are to select the equation that can be used to solve that problem. Yet, I cannot find out from @kitsune0724 what that problem is.

Answer 19

There's no problem given @Directrix. I'm sorry.

Answer 20

@kitsune0724 Why did you pick the third choice?

And, I know two of the choices cannot be identical. So, there's something faulty about this problem. I cannot help without more information.

The choices are: ... SAME x+(x+2)+(x+4)+(x+6)=636, SAME x+(x+2)+(x+4)+(x+6)=636 ....

Answer 21

@kitsune0724 I'm going to try to get a fresh pair of eyes for this problem. Hold on.

Answer 22

@Directrix it says if x is the smallest integer then ....
thus P = x is the smallest integer
this is never true^^^^^^
thus we have ~P which implies Q is true for any Q.
we have 4 Q's

Answer 23

all true....

Answer 24

@saifoo.khan --> We need a fresh pair of eyes on this problem. Would you render your thoughts, please? Thanks.

Answer 25

I dont see why you would try and solve a problem that cant be solved.....
if x is an irrational rational number what is x^2 <----would you try and solve this?

Answer 26

I don't really get the question. Sorry. :/

Are you sure it's complete? @kitsune0724

Answer 27

Thank y'all for your help.

Answer 28

Glad to try to help. It was a mathematical adventure. :)