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log base 3 (x-9) + log base 3 (x-3) = 2
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a law of logs says that \[\log_{a} b +\log_{a} c =\log_{a}bc \] try now
log base 3 (x-9)(x-3)=2
base3 xsquared -12x + 27 = 2
hint : setting in Right side be log base3 9
i dont understand
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yeah then you can change that to \[3^{2}=x ^{2}-12x+27\]
another rule of logs
2 = log base3 9, right ? because 3^2 = 9
x^2-12x=-18
hint: form a quadratic to use the quadratic formula
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