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Precalculus 7 Online
OpenStudy (anonymous):

The manager of a furniture factory finds that it costs $2200 to manufacture 100 chairs in one day and $4400 to produce 300 chairs in one day. (a) Assuming that the relationship between cost C and the number of chairs produced x is linear, find an equation that expresses this relationship.

OpenStudy (kropot72):

The equation will be of the form C = mx + b where C is the cost per chair, x is the number of chairs produced per day, m is the slope of the line and b is a constant. When x = 100, C = 2200/100 = $22 per chair When x = 300, C = 4400/300 = $14.67 per chair M can be found from the following formula: \[m=\frac{y _{1}-y _{2}}{x _{1}-x _{2}}=\frac{C _{1}-C _{2}}{x _{1}-x _{2}}=\frac{22-14.67}{100-300}=you\ can\ calculate\] When you have found m, substitute the value and values of C and x into C = mx + b and solve to find the value of b.

OpenStudy (anonymous):

i think it might be (C-2200) = ((4400-2200)/(300-100) ) * (x-100) C-2200=((2200/200)) *(x-100) C=11x-1100+2200 C=11x +1100

OpenStudy (whpalmer4):

@kropot72 You were a bit too clever for your own good. The problem is asking for the relationship between total cost and chairs produced, not cost per chair. Your line will have a negative slope because the cost per chair goes down as volume goes up, but the total cost has a positive slope as we never have a negative marginal cost to produce another chair.

OpenStudy (whpalmer4):

Though reading the problem again, reasonable people could differ on the meaning of "cost C", I'll admit!

OpenStudy (kropot72):

@whpalmer4 I think your interpretation is what was wanted by the setter of the question.

OpenStudy (whpalmer4):

I'd give medals to both of you if I could :-)

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