Question

Consider g(x)=3sin2x ,write down the period of g

Answer 1

period of \(\sin(bx)\) is always \(\frac{2\pi}{b}\)

Answer 2

in your case you get \(\frac{2\pi}{2}=\pi\) as the period

Answer 3

Is the 3 irrelevant when it comes to finding the period?

Answer 4

yes

Answer 5

that gives you the "amplitude"

Answer 6

since sine goes from -1 to 1, \(3\sin(x)\) goes from -3 to 3

Answer 7

allright, thank you for your help!!! much appreciated

Answer 8

sine does everything between 0 and \(2\pi\) for the input
if \(2x=0\) then \(x=0\) and if \(2x=2\pi\) then \(x=\pi\) so this goes through one period from \(0\) to \(\pi\)

Answer 9

yw