Question

Algebra 2 help please!?

Simplify the sum. State any restrictions on the variables.

Answer 1

Hint: Multiply the first fraction by (x - 3)/(x-3)

Answer 2

so would it become \[\frac{ x ^{2} + 5x + 6 }{ x ^{2} - 9 }\] @Hero

Answer 3

are you posting one of the multiple choices ?

Answer 4

This isn't a multiple choice problem

Answer 5

you have the wrong sign on 5x

Answer 6

Actually the numerator should be x^2 - 5x + 6

Answer 7

Okay, then what would I do?

Answer 8

once you have a common denominator, you can combine the tops

Answer 9

Since you are adding fractions, you need a common denominator.
The denominator of the left fraction is simply x + 3.
You need to factor the denominator of the right fraction.
x^2 - 9 = (x + 3)(x - 3)

Answer 10

Since the right denominator has factors (x + 3)(x - 3) and the left fraction only has
(x + 3), you need to multiply the numerator and denominator of the left fraction by
(x - 3).

Answer 11

Okay, I get you so far

Answer 12

Then multiply out the numerator of the left fraction (x + 3)(x - 2)

Answer 13

Okay I did that