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I really need help solving this. 0.5x-7<1.5+0.8x. Write in interval notation.
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First get all of the x terms to one side of the inequality. What do you get?
-7<1.5+0.3x
Yes. Now get x by itself on one side
Ok so would it be -5.5/0.3<x?
No. If you subtract 1.5 from both sides, you have 0.3x > -8.5 hence x > 85/3 = 28 1/3
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Oh ok. So how would I write that in interval notation?
Well, if x > a for some constant a, how do you write that in interval notation? It is \[ x \in (a, \infty) \]
so the answer would be (28,oo)? Im still confused.
No. It is \[ x \in (28 \frac{1}{3}, \infty) \] or \[ x \in (83/3, \infty) \] whichever you prefer.
oh ok. thanks you so much.
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