Question

Use the appropriate formula to find the indicated sums:

Answer 1

\[\sum_{i=1}^{50}(2i-1)^{2}\]

Answer 2

\[(2i-1)^2=4i^2-4i+1\]

Answer 3

\[4\sum i^2-4\sum i +\sum 1\]

Answer 4

oh i see.

Answer 5

now i just use my formulas.

Answer 6

then
\[\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}{6}\]for the the first one

\[\sum_{i=1}^ni=\frac{n(n+1)}{2}\] for the second and
\[\sum_{i=}^ni=n\] for the third

Answer 7

yes exactly

Answer 8

now do i sub in 50 for n?

Answer 9

yes

Answer 10

i have another one if you dont mind helping me.

Answer 11

@satellite73