Question

Integral from 0 to pi/2 of cos(x)sin(sinx)dx

Answer 1

try using integratio by parts

Answer 2

nah, try \(u=\sin(x)\)

Answer 3

\[u=\sin(x), du = \cos(x)dx, u(0)=0, u(\frac{\pi}{2})=1\] turn in to
\[\int_0^1udu\]

Answer 4

no sorry it is
\[\int_0^1\sin(u)du\] sorry