Given segment AB with endpoints A(2x, 4y) and B(10, 22), what is the midpoint?

Question

whpalmer4 · Answer

Midpoint of a line between $(x_1, y_1)$ and $(x_2,y_2)$ is gotten by averaging the corresponding values:

$$M = (\frac{1}{2}*(x_1+x_2), \frac{1}{2}*(y_1+y_2))$$

anonymous · Answer

i got 19?

anonymous · Answer

@whpalmer4

whpalmer4 · Answer

No, you should get a point — an x value and a y value.

whpalmer4 · Answer

$$((1/2)(2x + 10), (1/2)(4y + 22))$$

whpalmer4 · Answer

What is $$(1/2)(2x+10)$$?  The answer to that will be the x value of the midpoint.

whpalmer4 · Answer

Similarly, the value of $$(1/2)(4y+22)$$will be the y value of the midpoint.  Good luck!

anonymous · Answer

a^2+b^2= c^2

11^2+14^2= c^2, where c is the diagonal.
121+196=c^2

c=sqr(317)= 17.804 or about 18 inches.

whpalmer4 · Answer

No, that's the distance formula...you wanted the midpoint.

whpalmer4 · Answer

Unless you are talking about a new problem now...someone else will have to help, I have to leave.