Question

Line segment EF has endpoints at E(-2, 1) and F(-5, 5). Line segment GH has endpoints at G(-1, -2) and H(3, 1). What are their lengths?

Answer 1

@jim_thompson5910, can you please help me?

Answer 2

Let's find the length of EF


This is the same as finding the distance between points E and F


To find the distance between any two points, use the distance formula


d = sqrt((x2-x1)^2+(y2-y1)^2)


d = sqrt((-5-(-2))^2+( 5- 1)^2) ... Note: (x1,y1) is the first point (-2, 1) and (x2,y2) is the second point (-5, 5).


d = sqrt((-5+2)^2+( 5- 1)^2)


d = sqrt((-3)^2+(4)^2)


d = sqrt(9+16)


d = sqrt(25)


d = 5


So exact distance between the two points is 5 units.


Therefore, EF is 5 units long.


I'll let you find the length of GH

Answer 3

I got 5 for GH?

Answer 4

Same here, good job

Answer 5

Thanks :) !

Answer 6

you're welcome